(2y^2+3-y)-(2+2y^2-5y)=

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Solution for (2y^2+3-y)-(2+2y^2-5y)= equation:


Simplifying
(2y2 + 3 + -1y) + -1(2 + 2y2 + -5y) = 0

Reorder the terms:
(3 + -1y + 2y2) + -1(2 + 2y2 + -5y) = 0

Remove parenthesis around (3 + -1y + 2y2)
3 + -1y + 2y2 + -1(2 + 2y2 + -5y) = 0

Reorder the terms:
3 + -1y + 2y2 + -1(2 + -5y + 2y2) = 0
3 + -1y + 2y2 + (2 * -1 + -5y * -1 + 2y2 * -1) = 0
3 + -1y + 2y2 + (-2 + 5y + -2y2) = 0

Reorder the terms:
3 + -2 + -1y + 5y + 2y2 + -2y2 = 0

Combine like terms: 3 + -2 = 1
1 + -1y + 5y + 2y2 + -2y2 = 0

Combine like terms: -1y + 5y = 4y
1 + 4y + 2y2 + -2y2 = 0

Combine like terms: 2y2 + -2y2 = 0
1 + 4y + 0 = 0
1 + 4y = 0

Solving
1 + 4y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4y = 0 + -1
4y = 0 + -1

Combine like terms: 0 + -1 = -1
4y = -1

Divide each side by '4'.
y = -0.25

Simplifying
y = -0.25

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